How do you find #2p^2 + 3p - 4# less #- 2p^2 - 3p + 4#? Algebra Polynomials and Factoring Addition and Subtraction of Polynomials 1 Answer Luca F. Jun 10, 2015 #2p^2 + 3p - 4# less #- 2p^2 - 3p + 4# is #2(2p^2+3p-4)#. Explanation: The expression you wrote means #2p^2 + 3p - 4 - (- 2p^2 - 3p + 4)=# #2p^2+3p-4+2p^2+3p-4=# #4p^2+6p-8=# #2(2p^2+3p-4)#. Answer link Related questions How do you add two polynomials? How do you subtract two polynomials? How do you add and simplify #3x^2-4x+7# and #2x^3-4x^2-6x+5#? How do you subtract #5b^2-2a^2# from #4a^2-8ab-9b^2#? How do you simplify #(6.9a^2-2.3b^2+2ab)+(3.1a-2.5b^2+b)#? How do you simplify #(-t+15t^2)-(5t^2+2t-9)#? How do you subtract #(-5m^2-m)-(3m^2+4m-5)#? How do you add two polynomials if they don't have like terms? How do you simplify #(3a+4b)-(-6a-3b)#? How do you subtract #(x^2-8x+7)-(6x^2+7x-3)#? See all questions in Addition and Subtraction of Polynomials Impact of this question 5887 views around the world You can reuse this answer Creative Commons License