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How do you find a polynomial function of degree 4 with -1 as a zero of multiplicity 3 and 0 as a zero of multiplicity 1?

1 Answer

Jun 6, 2015

Just multiply:

${(x + 1)}^{3} \cdot (x - 0)$ $(x+1)^3*(x-0)$

$= (x^{3} + 3 x^{2} + 3 x + 1) x$ $=(x^3+3x^2+3x+1)x$

$= x^{4} + 3 x^{3} + 3 x^{2} + x$ $=x^4+3x^3+3x^2+x$

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