How do you find a polynomial function that has zeros 0, 2, 5? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer Alan N. Feb 10, 2017 f(x)=x^3-7x^2+10xf(x)=x3−7x2+10x Explanation: Let f(x)f(x) be the required polynomial. We are told that f(x)=0f(x)=0 for x={0, 2, 5}x={0,2,5} Thus: x, (x-2), (x-5)x,(x−2),(x−5) must be factors of f(x)f(x) :. f(x) = x(x-2)(x-5) = x(x^2-7x+10) =x^3-7x^2+10x Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of f(x) = 5x^7 − x + 216? What are the zeros of f(x)= −4x^5 + 3? How many times does f(x)= 6x^11 - 3x^5 + 2 intersect the x-axis? What are the real zeros of f(x) = 3x^6 + 1? How do you find the roots for 4x^4-26x^3+50x^2-52x+84=0? What are the intercepts for the graphs of the equation y=(x^2-49)/(7x^4)? See all questions in Zeros Impact of this question 6922 views around the world You can reuse this answer Creative Commons License