How do you find a polynomial function that has zeros 0, 2, 5?

1 Answer
Feb 10, 2017

f(x)=x^3-7x^2+10xf(x)=x37x2+10x

Explanation:

Let f(x)f(x) be the required polynomial.

We are told that f(x)=0f(x)=0 for x={0, 2, 5}x={0,2,5}

Thus: x, (x-2), (x-5)x,(x2),(x5) must be factors of f(x)f(x)

:. f(x) = x(x-2)(x-5)

= x(x^2-7x+10)

=x^3-7x^2+10x