Question

How do you find a polynomial function with zeroes 3,-2,1?

Answer 1

The polynomial is: `x^3-2x^2-5x+6`

Explanation:

When a number `a` is a zero of a polynomial, then this polynomial is divisible by `(x-a)`, so to find the polynomial with zeros `-2,1,3` you have to multiply `(x+2)(x-1)(x-3)`

`(x+2)(x-1)(x-3)=(x^2+x-2)*(x-3)=x^3+x^2-2x-3x^2-3x+6=x^3-2x^2-5x+6`