How do you find a standard form equation for the line with (5,3); slope =4?
1 Answer
Oct 3, 2016
The standard form equation for this line is 4x -y = -23.
Explanation:
Putting the provided slope and point coordinates into the point-slope form of a line will allow us to transform the equation into standard form. Point-slope form is y - y-sub-1 = m(x + x-sub-1). I am using -sub-1 to indicate a sub scripted number 1. I couldn't make the 1 sub scripted. The sub scripted y and x refer to the given point coordinates. Standard form is Ax + By = C, where A, B, and C are integers and A is positive. So, we begin:
y - 3 = 4(x + 5)
y - 3 = 4x + 20
y - 3 + 3 = 4x + 20 + 3
y = 4x + 23
-4x + y = 4x -4x + 23
-4x + y = 23
-1(-4x + y = 23)
4x - y = -23
