Question

How do you find a standard form equation for the line with m = -6, passing through (0, -8)?

Answer 1

The equation of the line is `y= -6x -8`

Explanation:

Let the equation of the line is `y=mx+c`. Here `m= -6; :.y= -6x +c`. The point (0,-8) satisfy the equation as it is on the liine `:. -8 = -6*0 +c or c= -8`Hence the equation of the line is `y= -6x -8`[Ans]