How do you find all points on the graph of $f (x) = {sin}^{2} x$ $f(x)=sin^2x$ at which the tangent line is horizontal?

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Answer 1 · 2016-11-08T13:50:04

graph{(sinx)^2 [-10, 10, -5, 5]}

$kpi/2 \ \ \ ;\ \ \ kinZZ$

$f^'(x)=2sinxcosx=sin2x$

$sin(2x)=0\ \ \$ when $\ \ \ \2x=kpi\ \ \ ; \ \ \ k in ZZ$

How do you find all points on the graph of f(x)=sin^2xf(x)=sin2xf(x)=sin^2x at which the tangent line is horizontal?