Question

How do you find all the values that make the expression undefined: `(3z^2 + z)/(18z + 6)`?

Answer 1

`z="no value"`

Explanation:

If you were to take the function as it is, then `18z+6!=0`
`18z!=-6`
`z!=-6/18=-1/3`

However, we can simplify the function:
`(z(3z+1))/(6(3z+1))`

`(zcancel((3z+1)))/(6cancel((3z+1)))=z/6` and therefore all values will be defined.