How do you find all the zeros of $f (x) = 3 (x + 5) {(x + 2)}^{2}$ $f(x) = 3(x+5)(x+2)^2$ ?

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Answer 1 · 2016-03-25T06:23:57

Zeros of $f (x)$ $f(x)$ are $- 5$ $-5$ and $- 2$ $-2$ .

If $a$ $a$ is a zero for a function $f (x)$ $f(x)$ , then $f (a) = 0$ $f(a)=0$ .

As the given $f (x) = 3 (x + 5) {(x + 2)}^{2} = 0$ $f(x)=3(x+5)(x+2)^2=0$ for $x + 5 = 0$ $x+5=0$ and $x + 2 = 0$ $x+2=0$ ,

the zeros of $f (x)$ $f(x)$ are $- 5$ $-5$ and $- 2$ $-2$ .

How do you find all the zeros of f(x)=3(x+5)(x+2)2f(x) = 3(x+5)(x+2)^2 ?