How do you find all the zeros of $f (x) = x^{2} + 5 x + 6$ $f(x) = x^2 + 5x +6$ ?

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Answer 1 · 2016-08-05T22:48:35

The zeros of $f (x)$ $f(x)$ are $x = - 2$ $x=-2$ and $x = - 3$ $x=-3$

Note that $2 + 3 = 5$ $2+3 = 5$ and $2 \times 3 = 6$ $2xx3 = 6$

So we find:

$f (x) = x^{2} + 5 x + 6 = (x + 2) (x + 3)$ $f(x) = x^2+5x+6 = (x+2)(x+3)$

Hence the zeros of $f (x)$ $f(x)$ are $x = - 2$ $x=-2$ and $x = - 3$ $x=-3$

How do you find all the zeros of f(x)=x2+5x+6f(x) = x^2 + 5x +6?