How do you find all the zeros of #f(x)= x^3-4x^2+3x#? Precalculus Polynomial Functions of Higher Degree Zeros 1 Answer A. S. Adikesavan Mar 4, 2016 0, 1 and 3. Explanation: f(x) = #x(x^2-4x+3)= x(x-1)(x-3)#. Equate each factor to 0. Answer link Related questions What is a zero of a function? How do I find the real zeros of a function? How do I find the real zeros of a function on a calculator? What do the zeros of a function represent? What are the zeros of #f(x) = 5x^7 − x + 216#? What are the zeros of #f(x)= −4x^5 + 3#? How many times does #f(x)= 6x^11 - 3x^5 + 2# intersect the x-axis? What are the real zeros of #f(x) = 3x^6 + 1#? How do you find the roots for #4x^4-26x^3+50x^2-52x+84=0#? What are the intercepts for the graphs of the equation #y=(x^2-49)/(7x^4)#? See all questions in Zeros Impact of this question 3239 views around the world You can reuse this answer Creative Commons License