How do you find all the zeros of $f(x) = (x + 3)(x – 1)(x – 5)$ ?

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Answer 1 · 2016-03-16T03:44:00

${-3,1,5}$ are zeros of #f(x)=(x+3)x-1)(x-5)

Zeros of $f(x)$ are those values of $x$ , which make $f(x)=0$ .

As $f(x)=(x+3)x-1)(x-5)$ , $f(x)$ will be zero, if

$x+3)=0$ or $x-1)=0$ or $(x-5)=0$ i.e.

$x=-3$ or $x=1$ or $x=5$

Hence, ${-3,1,5}$ are zeros of $f(x)=(x+3)x-1)(x-5)$

How do you find all the zeros of f(x) = (x + 3)(x – 1)(x – 5) f(x) = (x + 3)(x – 1)(x – 5)?