How do you find all the zeros of $x^{2} + x - 72 = 0$ $x^2 + x -72 = 0$ ?

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Answer 1 · 2016-03-21T18:38:00

$x = - 9 or x = 8$ $x=-9 or x=8$

$x^{2} + x - 72 = 0$ $x^2+x-72=0$
$(x + 9) (x - 8) = 0$ $(x+9)(x-8)=0$
$x = - 9 or x = 8$ $x=-9 or x=8$

How do you find all the zeros of x2+x−72=0x^2 + x -72 = 0?