How do you find all the zeros of x53x4+5x3+9x2+x2?

1 Answer
Jun 10, 2016

Use a numerical method to find approximations:

x10.390503

x2,32.01006±2.24677i

x4,50.705308±0.257059i

Explanation:

f(x)=x53x4+5x3+9x2+x2

By the rational root theorem, any rational zeros of f(x) are expressible in the form pq for integers p,q with p a divisor of the constant term 2 and q a divisor of the coefficient 1 of the leading term.

So the only possible rational zeros are:

±1, ±2

Neither of these is a zero, so f(x) has no rational zeros.

In common with quintics in general, this f(x) has no algebraic solution in terms of nth roots.

We can find rational approximations using a numeric method such as Durand-Kerner. For another example of such a quintic solution, see: https://socratic.org/s/avdSNDdg

In the current example we find approximations:

x10.390503

x2,32.01006±2.24677i

x4,50.705308±0.257059i

I used the following C++ program:

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