How do you find all the zeros of x5+x330x?

1 Answer
Jul 8, 2018

Factor to find zeros:

0,±5 and ±6i

Explanation:

After separating out the common factor x, the remaining quartic can be factored like a quadratic, before reducing to linear factors:

x5+x330x=x(x4+x230)

x5+x330x=x(x2+6)(x25)

x5+x330x=x(x6i)(x+6i)(x5)(x+5)

Hence zeros:

0,±5 and ±6i