How do you find all zeros of $f (x) = 49 - x^{2}$ $f(x)=49-x^2$ ?

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Answer 1 · 2017-03-01T01:10:48

x= -7, x=7

Set 49- $x^{2}$ $x^2$ = 0 and factor

You'll get (x-7)(x+7)
You can check if you factored correctly by distributing or using F.O.I.L

Now you have to set (x-7)(x+7) equal to 0 and solve for x.

Treat them as two separate equations
So...

(x-7) = 0 (x+7) = 0
Once you solve for x you'll find that x is equal to 7 and -7 and these are your zeros.

How do you find all zeros of f(x)=49−x2f(x)=49-x^2?