How do you find all zeros of h(t)=t^2-6t+9h(t)=t2−6t+9?

1 Answer
Bhaskar B.
Mar 5, 2018

3, that is the only root of h(t)h(t).

Explanation:

h(t)h(t) is a quadratic in tt which is :
h(t)=t^2-6t+9h(t)=t2−6t+9
to find its zeros we equate the function with 0.
h(t) = 0 => t^2-6t+9 = 0h(t)=0⇒t2−6t+9=0

Now by splitting the middle term,
=>t^2 -3t -3t +9= 0⇒t2−3t−3t+9=0
=>t(t-3)-3(t-3) = 0⇒t(t−3)−3(t−3)=0
=>(t-3)(t-3) = 0⇒(t−3)(t−3)=0

Hence the root is 3.

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