How do you find all zeros of the function $2 x^{3} - 3 x^{2} - 16 x + 10$ $2x^3-3x^2-16x+10$ ?

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How do you find all zeros of the function $2 x^{3} - 3 x^{2} - 16 x + 10$ $2x^3-3x^2-16x+10$ ?

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Answer 1 · 2016-03-29T22:41:42

I will graph this as a function, $f (x) = 2 x^{3} - 3 x^{2} - 16 x + 10$ $f(x) = 2x^3-3x^2-16x+10$ . my screenshot 6

Explanation:

Notice that -2.5 seems to be the "nicest" zero. That means 2x+5 is a factor. If you do long division on the original polynomial by 2x+5, you will get $x^{2} - 4 x + 2$ $x^2-4x+2$ . You can solve that quadratic with the quadratic formula to get: $2 + \sqrt{2}, 2 - \sqrt{2}$ $2+sqrt(2), 2-sqrt(2)$ .

my screenshot 7

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How do you find all zeros of the function $2 x^{3} - 3 x^{2} - 16 x + 10$ $2x^3-3x^2-16x+10$ ?

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How do you find all zeros of the function 2x3−3x2−16x+102x^3-3x^2-16x+10?

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How do you find all zeros of the function $2 x^{3} - 3 x^{2} - 16 x + 10$ $2x^3-3x^2-16x+10$ ?