How do you find all zeros of the function $f (x) = 10 x^{2} + 5 x - 5$ $f(x)=10x^2+5x-5$ ?

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Answer 1 · 2016-08-05T22:46:38

$f (x)$ $f(x)$ has zeros $x = \frac{1}{2}$ $x=1/2$ and $x = - 1$ $x=-1$

$f (x) = 10 x^{2} + 5 x - 5 = 5 (2 x^{2} + x - 1) = 5 (2 x - 1) (x + 1)$ $f(x) = 10x^2+5x-5=5(2x^2+x-1)=5(2x-1)(x+1)$

Hence $f (x)$ $f(x)$ has zeros $x = \frac{1}{2}$ $x=1/2$ and $x = - 1$ $x=-1$

How do you find all zeros of the function f(x)=10x2+5x−5f(x)=10x^2+5x-5?