How do you find all zeros of the function $f (x) = 2 {(x + 9)}^{2} {(x - 9)}^{3}$ $f(x)=2(x+9)^2 (x-9)^3$ ?

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How do you find all zeros of the function $f (x) = 2 {(x + 9)}^{2} {(x - 9)}^{3}$ $f(x)=2(x+9)^2 (x-9)^3$ ?

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Answer 1 · 2016-11-18T10:41:52

$x = - 9 O r x = 9$ $" " x=-9" " Or " " x=9$

Explanation:

$f (x) = 0$ $f(x) = 0$
$" "$
$2 {(x + 9)}^{2} {(x - 9)}^{3} = 0$ $2(x+9)^2(x-9)^3=0$
$" "$
${(x + 9)}^{2} = 0 \Rightarrow x + 9 = 0 \Rightarrow x = - 9$ $(x+9)^2=0" "rArr x+9=0" "rArr x=-9$
$" "$
Or
$" "$
${(x - 9)}^{3} = 0 \Rightarrow x - 9 = 0 \Rightarrow x = 9$ $(x-9)^3=0" "rArrx-9=0" "rArrx=9$
$" "$
$" "$
Hence, $x = - 9 O r x = 9$ $" " x=-9" " Or " " x=9$

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How do you find all zeros of the function $f (x) = 2 {(x + 9)}^{2} {(x - 9)}^{3}$ $f(x)=2(x+9)^2 (x-9)^3$ ?

1 Answer

Explanation:

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How do you find all zeros of the function f(x)=2(x+9)2(x−9)3f(x)=2(x+9)^2 (x-9)^3?

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How do you find all zeros of the function $f (x) = 2 {(x + 9)}^{2} {(x - 9)}^{3}$ $f(x)=2(x+9)^2 (x-9)^3$ ?