How do you find all zeros of the function $f (x) = - 2 x^{2} + 2 x + 4$ $f(x)=-2x^2+2x+4$ ?

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Answer 1 · 2016-08-05T22:32:58

$f (x)$ $f(x)$ has zeros $2$ $2$ and $- 1$ $-1$

$f (x) = - 2 x^{2} + 2 x + 4 = - 2 (x^{2} - x - 2) = - 2 (x - 2) (x + 1)$ $f(x) = -2x^2+2x+4=-2(x^2-x-2)=-2(x-2)(x+1)$

Hence the zeros of $f (x)$ $f(x)$ are $x = 2$ $x=2$ and $x = - 1$ $x=-1$

How do you find all zeros of the function f(x)=−2x2+2x+4f(x)=-2x^2+2x+4?