How do you find all zeros of the function $x² + 2x – 48 = 0$ ?

Question

2700 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-06-05T15:25:49

$x=-8$ or $x=6$

Let's factor $x^2+2x-48$

by finding two numbers whose sum is 2 and product is -48

the numbers are 8 and -6

so
$x^2+2x-48=(x+8)(x-6)$

that's zero when $x=-8$ or $x=6$

How do you find all zeros of the function x² + 2x – 48 = 0 x² + 2x – 48 = 0 ?