How do you find an equation of the circle whose center is (-3,1) and whose radius is 8?
1 Answer
May 8, 2018
Explanation:
"the equation of a circle in standard form is"
color(red)(bar(ul|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|))
"where "(a,b)" are the coordinates of the centre and r"
"is the radius"
"here "(a,b)=(-3,1)" and "r=8
(x-(-3))^2+(y-1)^2=8^2
rArr(x+3)^2+(y-1)^2=64larrcolor(red)"equation of circle"