How do you find an equation of the circle whose center is (-3,1) and whose radius is 8?
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"How do I solve #y'' + y = -2 sin(x)# with the initial conditions #y(0) = 0# and #y'(0) = 1#?"
1 Answer
May 8, 2018
Explanation:
#"the equation of a circle in standard form is"#
#color(red)(bar(ul|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|))#
#"where "(a,b)" are the coordinates of the centre and r"#
#"is the radius"#
#"here "(a,b)=(-3,1)" and "r=8#
#(x-(-3))^2+(y-1)^2=8^2#
#rArr(x+3)^2+(y-1)^2=64larrcolor(red)"equation of circle"#
