How do you find an equation of the circle whose center is (-3,1) and whose radius is 8?

1 Answer
May 8, 2018

(x+3)^2+(y-1)^2=64

Explanation:

"the equation of a circle in standard form is"

color(red)(bar(ul|color(white)(2/2)color(black)((x-a)^2+(y-b)^2=r^2)color(white)(2/2)|))

"where "(a,b)" are the coordinates of the centre and r"
"is the radius"

"here "(a,b)=(-3,1)" and "r=8

(x-(-3))^2+(y-1)^2=8^2

rArr(x+3)^2+(y-1)^2=64larrcolor(red)"equation of circle"