How do you find angle A in the following triangle, length of a = 17cm angle c = 105, Length of C = 37cm?
1 Answer
Mar 7, 2017
Explanation:
Using the
#color(blue)"sine rule"# in the triangle.
#color(red)(bar(ul(|color(white)(2/2)color(black)(a/sinA=c/sinC)color(white)(2/2)|)))#
#rArr(17)/sinA=37/sin105^@#
#color(blue)"cross-multiply"#
#rArr37sinA=17sin105^@#
#rArrsinA=(17sin105^@)/37#
#rArrA=sin^-1((17sin105^@)/37)#
#rArr"angle A "≈26.35^@" to 2 decimal places"#