Question

How do you find average value of function `h(r) = 3 / (1+r)^2` on given interval [1, 6]?

Answer 1

`3/14`

Average value would be `1/(6-1` `int_1^6 3/(1+r)^2` dr. Integrate using the power rule formula to get `1/5` (3) `[`-1/(1+r)`]_1^6`.

`3/5`[-`1/7` +`1/2`]= `3/14`