Question

How do you find cartesian equation the parametric equations of a circle are `x=cos theta -4` and `y=sin theta + 1`?

Answer 1

`(x+4)^2+(y-1)^2=1`

Explanation:

From `x=cos(theta)-4`, `cos(theta)=x+4` and from `y=sin(theta)+1`, `sin(theta)=y-1`

Hence,

`(x+4)^2+(y-1)^2=(cos(theta))^2+(sin(theta))^2` or,

`(x+4)^2+(y-1)^2=1`