How do you find f'(1) if #f(x)= x^2*tan^-1 x#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer bp May 18, 2015 It would be #pi/2+1/2# f' (x)= #2x tan^-1 x + x^2 /(1+x^2)# f' (1)= # 2tan^-1 1+ 1/2# =#2pi/4 +1/2# =#pi/2 +1/2# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1337 views around the world You can reuse this answer Creative Commons License