How do you find parabola equation given vertex is (2,3) and the zeros are x=0 and x=4?
1 Answer
Jun 30, 2018
Explanation:
#"using the "color(blue)"intercept form"#
#•color(white)(x)y=k(x-a)(x-b)#
#"where a and b are the zeros and k is a multiplier"#
#"y=k(x-0)(x-4)=kx(x-4)#
#"to find k substitute "(2,3)" into the equation"#
#3=2k(-2)rArr-4k=3rArrk=-3/4#
#y=-3/4x(x-4)=-3/4x^2+3x#
graph{-3/4x^2+3x [-10, 10, -5, 5]}
