How do you find points of inflection and determine the intervals of concavity given #y=(3x+2)/(x-2)#?
1 Answer
There are no points of inflection.
The interval of concavity is
Explanation:
Calculate the first derivative
This is a quotient
Here,
Therefore,
And the second derivative is
The points of inflection are when
Here, the second derivative is
So, there are no points of inflection
Build a sign chart for the concavity
The interval of concavity is
graph{(3x+2)/(x-2) [-41.1, 41.08, -20.56, 20.56]}