How do you find real zero of a function $f (x) = x^{2} + 5 x + 6$ $f(x) = x^2 + 5x +6$ ?

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How do you find real zero of a function $f (x) = x^{2} + 5 x + 6$ $f(x) = x^2 + 5x +6$ ?

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Answer 1 · 2018-04-16T08:42:46

$x = - 3, x = - 2$ $x=-3,x=-2$

Explanation:

$equate f (x) to zero$ $"equate "f(x)" to zero"$

$\Rightarrow x^{2} + 5 x + 6 = 0 \leftarrow in standard form$ $rArrx^2+5x+6=0larrcolor(blue)"in standard form"$

$the factors of + 6 which sum to + 5 are + 3 and + 2$ $"the factors of + 6 which sum to + 5 are + 3 and + 2"$

$\Rightarrow (x + 3) (x + 2) = 0$ $rArr(x+3)(x+2)=0$

$equate each factor to zero and solve for x$ $"equate each factor to zero and solve for x"$

$x + 3 = 0 \Rightarrow x = - 3$ $x+3=0rArrx=-3$

$x + 2 = 0 \Rightarrow x = - 2$ $x+2=0rArrx=-2$
graph{x^2+5x+6 [-10, 10, -5, 5]}

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How do you find real zero of a function $f (x) = x^{2} + 5 x + 6$ $f(x) = x^2 + 5x +6$ ?

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Explanation:

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How do you find real zero of a function f(x)=x2+5x+6f(x) = x^2 + 5x +6?

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How do you find real zero of a function $f (x) = x^{2} + 5 x + 6$ $f(x) = x^2 + 5x +6$ ?