How do you find s[h(x)] if #s(x) = 2^x# and #h(x) = x^2#? Precalculus Functions Defined and Notation Function Composition 1 Answer mason m Jan 4, 2016 #s(h(x))=2^(x^2)# Explanation: #s(h(x))# is a way of saying put #h(x)# in #s(x)#. In other words, take #x^2#, and plug it in the spot where #x# is in #2^x#. #s(h(x))=2^(x^2)# Answer link Related questions What is function composition? What are some examples of function composition? What are some common mistakes students make with function composition? Is function composition associative? Is it always true that #(f@g)(x) = (g@f)(x)#? If #f(x) = x + 3# and #g(x) = 2x - 7#, what is #(f@g)(x)#? If #f(x) = x^2# and #g(x) = x + 2#, what is #(f@g)(x)#? If #f(x) = x^2# and #g(x) = x + 2#, what is #(g@f)(x)#? What is the domain of #(f@g)(x)#? What is the domain of the composite function #(g@f)(x)#? See all questions in Function Composition Impact of this question 1349 views around the world You can reuse this answer Creative Commons License