How do you find the acceleration for the function $s(t)=-16t^2+100t +20$ ?

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Answer 1 · 2018-06-04T18:32:42

$-32" unit."$

The velocity $v$ of the particle travelling distance $s$ in time $t$ is given

by, $v=(ds)/dt$ .

The acceleration $a$ then is $a=(dv)/dt=(d^2s)/dt^2$ .

$:. v=(ds)/dt=d/dt{s(t)}$

$=d/dt{-16t^2+100t+20}$

$=-16*2t+100$ .

$rArr v=-32t+100$ .

Then, $a=(dv)/dt=d/dt{-32t+100}=-32" unit."$

How do you find the acceleration for the function s(t)=-16t^2+100t +20s(t)=-16t^2+100t +20 ?