Question

How do you find the antiderivative of `1/(1-x)^2`?

Answer 1

I found: `1/(1-x)+c`

Explanation:

I tried this:
`int1/(1-x)^2dx=`
Where: `d[1-x]=-dx` giving:
`int(1-x)^-2*-dx=1/(1-x)+c`