How do you find the antiderivative of e2x1+(e4x)dx?
1 Answer
Dec 12, 2016
Explanation:
∫e2x1+e4xdx
Let
=12∫2e2x1+(e2x)2dx
=12∫11+u2du
This is the arctangent integral:
=12arctan(u)+C
=12arctan(e2x)+C
Another way to show this is to use the trigonometric substitution