Question

How do you find the antiderivative of `f(x)=1/5x^4-3/4x-1`?

Answer 1

`1/25x^(5)-3/8x^(2)-x+C`

Explanation:

Note `(a*1/(n+1)*x^(n+1))'=a*x^n`

`int1/5x^4-3/4x-1dx`

`1/5*1/(4+1)x^(4+1)-3/4*1/(1+1)x^(1+1)-x`

`1/5*1/(5)x^(5)-3/4*1/(2)x^(2)-x+C`

`1/25x^(5)-3/8x^(2)-x+C`