How do you find the antiderivative of #x^(3/2)#? Calculus Introduction to Integration Integrals of Polynomial functions 1 Answer Rajinder S. Oct 20, 2016 #2/5 sqrt x^5# + c Explanation: #int x^(3/2) dx# = #x^(3/2 + 1)/((3/2 +1)# = #x^(5/2)/(5/2)# = #2/5x^(5/2) + c# = #2/5 sqrt x^5 # + c Answer link Related questions How do you evaluate the integral #intx^3+4x^2+5 dx#? How do you evaluate the integral #int(1+x)^2 dx#? How do you evaluate the integral #int8x+3 dx#? How do you evaluate the integral #intx^10-6x^5+2x^3 dx#? What is the integral of a constant? What is the antiderivative of the distance function? What is the integral of #|x|#? What is the integral of #3x#? What is the integral of #4x^3#? What is the integral of #sqrt(1-x^2)#? See all questions in Integrals of Polynomial functions Impact of this question 6820 views around the world You can reuse this answer Creative Commons License