How do you find the antiderivative of #(x^(3) + 2x)/(x^(4) + 4x^(2) +2)#? Calculus Introduction to Integration Integrals of Rational Functions 1 Answer maganbhai P. Jun 29, 2018 #int(x^3+2x)/(x^4+4x^2+2)dx=1/4ln|x^4+4x^2+2|+c# Explanation: Here, #I=int(x^3+2x)/(x^4+4x^2+2)dx# #=1/4int(4x^3+8x)/(x^4+4x^2+2)dx# #=1/4int(d(x^4+4x^2+2))/(x^4+4x^2+2)dx# #=1/4ln|x^4+4x^2+2|+c# Answer link Related questions How do you integrate #(x+1)/(x^2+2x+1)#? How do you integrate #x/(1+x^4)#? How do you integrate #dx / (2sqrt(x) + 2x#? What is the integration of #1/x#? How do you integrate #(1+x)/(1-x)#? How do you integrate #(2x^3-3x^2+x+1)/(-2x+1)#? How do you find integral of #((secxtanx)/(secx-1))dx#? How do you integrate #(6x^5 -2x^4 + 3x^3 + x^2 - x-2)/x^3#? How do you integrate #((4x^2-1)^2)/x^3dx #? How do you integrate #(x+3) / sqrt(x) dx#? See all questions in Integrals of Rational Functions Impact of this question 3623 views around the world You can reuse this answer Creative Commons License