How do you find the area given $a = 12, b = 15, c = 9$ $a=12, b=15, c=9$ ?

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How do you find the area given $a = 12, b = 15, c = 9$ $a=12, b=15, c=9$ ?

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Answer 1 · 2017-05-25T03:08:07

Area $= 54$ $=54$ sq. units

Explanation:

Assuming $a, b and c$ $a, b and c$ are the three sides of a triangle we can apply Heron's formula to find the area.

Area $= \sqrt{p (p - a) (p - b) (p - c)}$ $=sqrt(p (p−a )(p− b)(p−c))$
where p is half the perimeter, or $\frac{a + b + c}{2}$ $(a+b+c)/2$ (often called the semi-perimeter)

In this example: $a = 12, b = 15, c = 9$ $a=12, b=15,c=9$

$p = \frac{12 + 15 + 9}{2} = 18$ $p=(12+15+9)/2 = 18$

Area $= \sqrt{18 (18 - 12) (18 - 15) (18 - 9)}$ $=sqrt(18(18-12)(18-15)(18-9))$

$= \sqrt{18 \times 6 \times 3 \times 9}$ $=sqrt(18xx6xx3xx9)$

$= \sqrt{2916}$ $=sqrt(2916)$

$= 54$ $=54$ sq. units

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How do you find the area given $a = 12, b = 15, c = 9$ $a=12, b=15, c=9$ ?

1 Answer

Explanation:

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Math

Humanities

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How do you find the area given a=12,b=15,c=9a=12, b=15, c=9?

1 Answer

Explanation:

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How do you find the area given $a = 12, b = 15, c = 9$ $a=12, b=15, c=9$ ?