How do you find the area of a triangle if height: #(4x^3y^4)^2# and base: #(xy)^2#?

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Answer 1 · 2018-04-01T05:03:15

#A=8x^8y^10#

For a triangle,

#A=1/2bh# where #b# is the base, #h# is the height.

We're given #h=(4x^3y^4)^2#

#b=(xy)^2#

So,

#A=1/2(4x^3y^4)^2(xy^2)#

Simplify:

#A=1/2(16x^6y^8)(x^2y^2)#

#A=8x^8y^10#