How do you find the area of a triangle with a=15, b=17, c=10?

Question

How do you find the area of a triangle with a=15, b=17, c=10?

1 Answer

Impact of this question

1885 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-10-04T13:31:27

Use Heron's formula to get

Explanation:

Heron's formula for the area of a triangle with sides of length $a, b, c$ $a, b, c$ is
$XXX A = \sqrt{s (s - a) (s - b (s - c))}$ $color(white)("XXX")A= sqrt(s(s-a)(s-b(s-c))$
where $s$ $s$ is the semi-perimeter (that is, $\frac{a + b + c}{2}$ $(a+b+c)/2$ )

Given $a = 15, b = 17, c = 10$ $a=15, b=17, c=10$
$s = 21$ $s=21$
and
$A = \sqrt{21 \cdot (21 - 15) \cdot (21 - 17) \cdot (21 - 10)}$ $A= sqrt(21 * (21-15) * (21-17) * (21-10))$

$XX = \sqrt{21 \cdot 6 \cdot 4 \cdot 11}$ $color(white)("XX")=sqrt(21*6*4*11)$

$XX = \sqrt{5544}$ $color(white)("XX")=sqrt(5544)$

$XX ≅ 74.46$ $color(white)("XX")~=74.46$

Science

Math

Humanities

... and beyond

How do you find the area of a triangle with a=15, b=17, c=10?

1 Answer

Explanation:

Related questions

Impact of this question