How do you find the area of a triangle with a base of 3 5/8 in. and a height of 2 1/2 in?

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How do you find the area of a triangle with a base of 3 5/8 in. and a height of 2 1/2 in?

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Answer 1 · 2018-07-14T15:09:51

$area = 4 \frac{17}{32} {in}^{2}$ $"area "=4 17/32" in"^2$

Explanation:

$the area (A) of a triangle is found using the formula$ $"the area (A) of a triangle is found using the formula"$

$∙ x A = \frac{1}{2} \times base \times height$ $•color(white)(x)A=1/2xx"base"xx"height"$

$here base = 3 \frac{5}{8} = \frac{29}{8} and height = 2 \frac{1}{2} = \frac{5}{2}$ $"here base "=3 5/8=29/8" and height "=2 1/2=5/2$

$A = \frac{1}{2} \times \frac{29}{8} \times \frac{5}{2} = \frac{145}{32} = 4 \frac{17}{32} {in}^{2}$ $A=1/2xx29/8xx5/2=145/32=4 17/32" in"^2$

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How do you find the area of a triangle with a base of 3 5/8 in. and a height of 2 1/2 in?

1 Answer

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