How do you find the area of the triangle given $C = 120^{\circ}, a = 4, b = 6$ $C=120^circ, a=4, b=6$ ?

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Answer 1 · 2018-03-07T15:08:01

Area of triangle $A_{t} = 6 \sqrt{3} = 10.39$ $color(red)(A_t = 6 sqrt3 = 10.39$ sq units

Area of a triangle can be calculated using formula

$A_{t} = (\frac{1}{2}) a b sin C$ $A_t = (1/2) a b sin C$ having known SAS measurements.

$G i v e n : a = 4, b = 6, ˆ C = 120^{\circ}$ $Given : a = 4, b = 6, hatC = 120^@$

$A_t = (1/2) 4 * 6 * sin 120 = (1/cancel2) * cancel(24)^color(red)(12) * sin (180 - 120)$

$A_t = 12 * sin 60 =( (cancel(12 )^color(red)(6) * sqrt3 ) / cancel2) = 6 sqrt3$

How do you find the area of the triangle given C=120^circ, a=4, b=6C=120∘,a=4,b=6C=120^circ, a=4, b=6?