How do you find the area of $△ A B C$ $triangle ABC$ given a=10, c=8, sinB=3/10?

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Answer 1 · 2017-02-10T10:15:13

$A_(DeltaABC)=12 " sq units"$

$"area of triangle is given by: "$

$A_Delta=1/2 a bsinC$

or

$A_Delta=1/2 b csinA$

or

$A_Delta=1/2 a csinB$

in this case will need the last form

$A_Delta=1/2 cancel(10)xx8xx3/cancel(10)$

$A_(DeltaABC)=24/2=12 " sq units"$

How do you find the area of triangle ABC△ABCtriangle ABC given a=10, c=8, sinB=3/10?