How do you find the area of $△ A B C$ $triangle ABC$ given a=24, b=12, sinC=3/4?

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Answer 1 · 2018-04-06T09:53:40

$108 sq.unit$ $108" sq.unit"$ .

From Trigonometry, we know that,

the Area of

$DeltaABC=1/2*a*bsinC=1/2*24*12*3/4=108" sq.unit"$ .

How do you find the area of triangle ABC△ABCtriangle ABC given a=24, b=12, sinC=3/4?