How do you find the area of $△ A B C$ $triangle ABC$ given a=326, c=157, $m ∠ B = 72$ $mangleB=72$ ?

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How do you find the area of $△ A B C$ $triangle ABC$ given a=326, c=157, $m ∠ B = 72$ $mangleB=72$ ?

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Answer 1 · 2016-12-26T03:21:34

$24338.5$ $24338.5$

Explanation:

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Area of a triangle - "side angle side" (SAS) method :

Area $= \frac{1}{2} \cdot a \cdot b \cdot sin C$ $=1/2*a*b*sinC$
where $a, b$ $a,b$ are the two known sides and $C$ $C$ is the included angle.

Given $a = 326, c = 157 and ∠ B = 72$ $a=326, c=157 and angleB=72$ ,
$\Rightarrow$ $=>$ Area $= \frac{1}{2} \cdot a \cdot c \cdot sin B$ $= 1/2*a*c*sinB$
$\Rightarrow$ $=>$ Area $= \frac{1}{2} \cdot 326 \cdot 157 \cdot sin 72 = 24, 338.5$ $=1/2*326*157*sin72=24,338.5$ $u n i t^{2}$ $unit^2$

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How do you find the area of $△ A B C$ $triangle ABC$ given a=326, c=157, $m ∠ B = 72$ $mangleB=72$ ?

1 Answer

Explanation:

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How do you find the area of △ABCtriangle ABC given a=326, c=157, m∠B=72mangleB=72?

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Explanation:

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How do you find the area of $△ A B C$ $triangle ABC$ given a=326, c=157, $m ∠ B = 72$ $mangleB=72$ ?