How do you find the area of $△ A B C$ $triangle ABC$ given b=9, c=16, sinA=5/6?

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Answer 1 · 2018-03-06T09:57:14

$60 sq.unit$ $60" sq.unit"$ .

Area of $DeltaABC=1/2bcsinA=1/2xx9xx16xx5/6=60" sq.unit"$ .

Answer 2 · 2018-03-06T10:10:32

$triangle=60$

We know that,area of $triangleABC=triangle=1/2bcsinA$
$:.triangle=1/2(9)(16)(5/6)=60$

How do you find the area of triangle ABC△ABCtriangle ABC given b=9, c=16, sinA=5/6?