How do you find the area of $△ A B C$ $triangle ABC$ given $C = 116^{\circ}, a = 2.7, b = 4.6$ $C=116^circ, a=2.7, b=4.6$ ?

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Answer 1 · 2018-01-27T11:52:30

Area $\approx 5.582$ $approx5.582$

The area of the triangle is $\frac{1}{2} \cdot a \cdot b \cdot sin (C)$ $1/2*a*b*sin(C)$ , so:

Area $= \frac{1}{2} \cdot 2.7 \cdot 4.6 \cdot sin (116^{\circ}) \approx 5.582$ $=1/2*2.7*4.6*sin(116^circ) approx5.582$

How do you find the area of △ABCtriangle ABC given C=116∘,a=2.7,b=4.6C=116^circ, a=2.7, b=4.6?