How do you find the area of $△ D E F$ $triangle DEF$ given e=336, f=257, $m ∠ D = 122$ $mangleD=122$ ?

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How do you find the area of $△ D E F$ $triangle DEF$ given e=336, f=257, $m ∠ D = 122$ $mangleD=122$ ?

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Answer 1 · 2017-01-05T02:49:01

$36 615.325 u n i t^{2}$ $36 615.325 unit^2$

Explanation:

$a r e a o f △ = \frac{1}{2} e f sin D$ $area of triangle = 1/2ef sin D$
$= \frac{1}{2} (336) (257) (sin 122)$ $= 1/2(336)(257)(sin122)$
$= 168 \cdot 257 \cdot 0.848$ $=168*257*0.848$

$36615.325 u n i t^{2}$ $36615.325 unit^2$

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How do you find the area of $△ D E F$ $triangle DEF$ given e=336, f=257, $m ∠ D = 122$ $mangleD=122$ ?

1 Answer

Explanation:

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Science

Math

Humanities

... and beyond

How do you find the area of △DEFtriangle DEF given e=336, f=257, m∠D=122mangleD=122?

1 Answer

Explanation:

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Impact of this question

How do you find the area of $△ D E F$ $triangle DEF$ given e=336, f=257, $m ∠ D = 122$ $mangleD=122$ ?