Question

How do you find the average rate of change for the function `f(x) = 4x^3 - 8x^2 - 3` on the indicated intervals [-5,2]?

Answer 1

The average rate of change for the function `f(x) = 4x^3 - 8x^2 - 3` on the interval `[-5,2]` is `(Deltaf)/(Deltax) = 100`

Explanation:

The average rate of change of function `f` on interval `[a,b]` is:

`(Deltaf)/(Deltax) = (f(b)-f(a))/(b-a)`

In this case, we have `a=-5`, abd `b = 2`, so we get:

`(Deltaf)/(Deltax) = (f(2)-f(-5))/(2-(-5))`

`= (-3-(-703))/7`

`= 700/7 = 100`