Question

How do you find the average rate of change for the function `f(x)=x^3+1` on the indicated intervals [2,3]?

Answer 1

The average rate of change of function `f` on interval `[a,b]` is: `(f(b)-f(a))/(b-a)`

Explanation:

In this question we have `f(x) = x^3+1`, so

`f(3) = (3)^3+1 = 28`

`f(2) = (2)^3 +1 = 9`

So `(f(3)-f(2))/(3-2) = (28-9)/(3-2) = 19/1 = 19`

The average rate of change is `19`